banned-users

say the 14 words to them

that would require me to have her server

which i dont

too much work

one of us

haha

do you play on NA?

ok Pika help pls

Calculate the equilibrium constant for the following reaction at 25°C. Fe2+(aq) + 2 Ag(s) equilibrium reaction arrow Fe(s) + 2 Ag+(aq)

no

damn FE 2 is in that equation

For Ecell i got 1.24, G would be (-2)(96500)(1.24) to get -239320 J

then it would be e^(-239320/-8.314x298) = 8.92e41 but thats wrong

@Phijkchu_Pikachu pls halp

I literally don't know chemistry it has been years since I have done it

fuk

Just make a baking soda volcano

boom, chemistry

that doesnt help my situation

pls i have a webassign due in 90ish mins and im at an 88 pls

maybe you should have done it sooner

its the last question

no but really I can't help you I flunked middle school level chemistry

all right 1 sec

let me go get my chem book

google it dolf

i did

all of the yahoo answers had like 5 dislikes

and chegg wants my money

is "Calculate the equilibrium constant for the following reaction at 25°C. Fe2+(aq) + 2 Ag(s) equilibrium reaction arrow Fe(s) + 2 Ag+(aq)" all they ask?

nothing else?

and pikas chegg loophole site still doesnt work

yes

hmm

which involced G = -nFE and G = -RTlnK

involves

https://www.khanacademy.org/science/chemistry/oxidation-reduction/electrochemistry-thermodynamics-and-equilibrium/v/calculating-the-equilibrium-constant-from-the-standard-cell-potential this explains the process

The E values for Fe2+ and Ag are -.44 and .80 respectively

where did he get 0.0592 V from

it is a constant

the equation my chem book has is E = E0 - (0.0592/n)logQ

I assume Q is just a different notation

alternatively, I am also working on this now

I remember this vaguely

if I did it right 1.17 x10^-30

the video is different from what we have been taught

wait

log base 10 not log 10

shit 1 sec

am i right in saying Ecell is 1.24 tho

I got Ecell = -2.04

is it because of the 2 Ag?

yes and you add them I believe

so you should have -0.44 from the Fe and -1.6 from the Ag

is it not +1.60?

bec you dont flip the Silver because its the most positive of the 2

1.60 - (-.44) = 2.04

I assumed you just do it so that it makes the correct equation

so you have to flip it to get the correct reaction order

idk again I have not done this in years

wait do you use E cathod and Eanode or Eoxid and Ered

same thing

What you wrote is equivalent to what I did if that is the case

no it is not

E cell = Eox + Ered or ECathode - Eanode

according to my textbook

Oxidation happens at the cathode and reduction at the anode

what i do to stop confusion over the SERP table is Ered -(-Ered)

Ecell = Ered(Cathode) - Ered(Anode)

alright umbreon I trust you

cool

I will not open it but it will drive me insane

why

idk he dmed me telling me not to open this