thx
banned-users
Phi Kappa Chi ΦΚΧ <a:yeah:589703000977571860><a:ppHop:536353159615086612>
Tuesday, February 12, 2019
Canada bauxite ore is moved into things;;; When functioning properly, the actual weights of ore loaded into each car by the filling equipment at the mine are approximately normally distributed with a mean of 70 tons and a standard deviation of 0.9 ton. If the mean is greater that 70 tons, the loading mechanism is overfilling.
If the filling equipment is functioning properly, what is the probability that the weight of the ore in a randomly selected car will be 70.7 tons or more? Show your work.
Suppose that the weight of the ore in a randomly selected car is 70.7 tons. Would that fact make you suspect that the loading mechanism is overfilling the cars? Justify your answer.
If the filling equipment is functioning properly, what is the probability that a random sample of 10 cars will have a mean ore weight of 70.7 tons or more? Show your work.
Based on your answer in part (c), if a random sample of 10 cars had a mean ore weight of 70.7 tons, would you suspect the loading mechanism was overfilling the cars? Justify your answer.
Suppouse that the distribution of adult weight is somewhat right-skewed with a mean of 175 pounds and a standard deviation of 25 pounds. A large elaveator has a weight limit of 7200 pounds if 40 adults enter what is the probability it exceeds the limit?and this
thx
that last question requires a 40 dimensional gaussian surface
the world only has 27 dimensions so its impossible
Wtf
I’m not even there and you still take a shot at me
Bruh 😐
guys
Six's discord made a minecraft smp
whats the ip
so i can uh
"build"
its whitelisted
shit
how to get whitelisted
just ask em in her server
say the 14 words to them
that would require me to have her server
which i dont
woopsHmm
too much work
dab
woopsHYPERCOMFY
one of us
@Kayla
haha
do you play on NA?
ok Pika help pls
Calculate the equilibrium constant for the following reaction at 25°C.
Fe2+(aq) + 2 Ag(s) equilibrium reaction arrow Fe(s) + 2 Ag+(aq)
damn FE 2 is in that equation
For Ecell i got 1.24, G would be (-2)(96500)(1.24) to get -239320 J
then it would be e^(-239320/-8.314x298) = 8.92e41 but thats wrong
@Phijkchu_Pikachu pls halp
I literally don't know chemistry it has been years since I have done it
fuk
Just make a baking soda volcano
boom, chemistry
that doesnt help my situation
pls i have a webassign due in 90ish mins and im at an 88 pls
maybe you should have done it sooner
its the last question
no but really I can't help you I flunked middle school level chemistry
all right 1 sec
let me go get my chem book
google it dolf
i did
all of the yahoo answers had like 5 dislikes
and chegg wants my money
is "Calculate the equilibrium constant for the following reaction at 25°C.
Fe2+(aq) + 2 Ag(s) equilibrium reaction arrow Fe(s) + 2 Ag+(aq)" all they ask?
nothing else?
and pikas chegg loophole site still doesnt work
yes
hmm
its looking for Kc
which involced G = -nFE and G = -RTlnK
involves
The E values for Fe2+ and Ag are -.44 and .80 respectively
where did he get 0.0592 V from
it is a constant
the equation my chem book has is E = E0 - (0.0592/n)logQ
I assume Q is just a different notation
alternatively, I am also working on this now
I remember this vaguely
if I did it right 1.17 x10^-30
the video is different from what we have been taught
log base 10 not log 10
shit 1 sec
am i right in saying Ecell is 1.24 tho
I got Ecell = -2.04
is it because of the 2 Ag?
yes and you add them I believe
so you should have -0.44 from the Fe and -1.6 from the Ag
is it not +1.60?
bec you dont flip the Silver because its the most positive of the 2