banned-users

dy/dx = 0

Or wait, it is xdy/dx

no

wait

wait

I am tired

ignore me

tbh

it shouldn't be xdy/dx

think you were right the first time

i had ((2 - dx/dy)(x-2y) - (1 - 2(dx/dy))(2x - y)) / (x-2y)^2

the fuck are you doing

first derivative is 2x + y = 0

woah

it's xddddd

division

lol max

xd

max send ndes

DX

ok

dm me for nudes

sending nodes

will take all the noodles

inb4 she just sends what i gave her yesterday

but yeah

nah

real nudes

dm me your ramen, your spagetti, your linguini

quotient rule for derivatives

woah leg sending nudes too

hit me with them leg

But yeah

leg is right

it is 2x - y

for first derivative

wait

i forgot

its =9

or rather a wierd oval

that doesn't affect it

so first is 2x-y / x-2y

no

it is 10000% that

ive tested this in desmos

literally me and leg have done this for years, you need to do the chain rule on the y derivative

you are definitely not telling us what the real question is

yeah

lol

given the curve x^2 - xy + y^2 = 9

i forgot the = 9

At the point (0,3) find the rate of change in the slope of the curve with respect to x

so double derivative

earlier i took single derivative

which was (2x-y)/(x-2y)

single derivative is 2x+y = 0

implicit differentiation

Which makes sense considering slope on a circle is a line

yes

my equation is same as wolfram alpha

so how do you derive the y if you are deriving with repect to x tho

walfram is wrong sometimes

but the equation works

I don't rememeber that

tested it in desmos with several points

so now i need to know the derivative of that

those are not sllopes of the tangent line btw

which now looking at it should be 2

nice adblock remove covering the steps pika

pika implicit differentiation means that y is implicitly a function of x

so the real question is x^2 - x*y(x) - y(x)^2 = 9

yes thats the real question

like i said i forgot the = 9

the 9 has nothing to do with why your question made no sense