banned-users

no not chem

I need to be asleep soon for a midterm

calc

I can do that

i need to find the double derivative of x^2-xy+y^2 at the point 0,3

derivative with respect to x?

ooo fun

likely pika

yes

its 2

i found the single derivative as (2x-y)/(x-2y)

you can cancel out the x-y

leg is correct

right?

its a problem set

i need to get there

if its with respect to only x there is no subtraction whatsoever

with work

2x - y - dy/dx = 0

wait wut

dy/dx = 0

Or wait, it is xdy/dx

no

wait

wait

I am tired

ignore me

tbh

it shouldn't be xdy/dx

think you were right the first time

i had ((2 - dx/dy)(x-2y) - (1 - 2(dx/dy))(2x - y)) / (x-2y)^2

the fuck are you doing

first derivative is 2x + y = 0

woah

it's xddddd

division

lol max

xd

max send ndes

DX

dm me for nudes

sending nodes

will take all the noodles

inb4 she just sends what i gave her yesterday

but yeah

nah

real nudes

dm me your ramen, your spagetti, your linguini

quotient rule for derivatives

woah leg sending nudes too

hit me with them leg

But yeah

leg is right

it is 2x - y

for first derivative

wait

i forgot

its =9

its a circle

or rather a wierd oval

that doesn't affect it

so first is 2x-y / x-2y

no

it is 10000% that

ive tested this in desmos

literally me and leg have done this for years, you need to do the chain rule on the y derivative

you are definitely not telling us what the real question is

yeah

lol

given the curve x^2 - xy + y^2 = 9

i forgot the = 9

At the point (0,3) find the rate of change in the slope of the curve with respect to x

so double derivative

earlier i took single derivative

which was (2x-y)/(x-2y)

single derivative is 2x+y = 0

implicit differentiation

Which makes sense considering slope on a circle is a line