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Friday, April 1, 2022
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Yes
lmao
good try dunce parse
lets not argue over math this time!
I guess a better metric is comparing start of month with start of month
he started last month with 286
gained 10
Replying to Phijkchu_Pikachu #klombak lets not argue over math this time! (edited)
True or False: The sum of the square roots any two sides of an isosceles triangle is equal to the square root of the remaining side?
is that the simpsons math thing you are referencing
I know they stated something like that
as a joke
oh lol
I think the simpsons also referenced it then at some point because that is where I thought of
That theorem is valid for isosceles triangles where the one side is 1/4th the size of the two equal size
although
I'd have to check to see if thats possible
and for the triangles to still actually geometrically work
I have concluded its not possible
not root
square
so a^2 + b^2 = c^2
the problem you stated reduces to finding all a such that this triangle is valid, but it can never be valid
since this triangle violates the Pyhtagorean theorem
since the hypotenuses needs to be the largest size
in this case its a
whereas one of the other sides is 2a
which is strictly always larger
for all a
Replying to Phijkchu_Pikachu #klombak I have concluded its not possible
I never tried to find out if it worked whatsoever with an isosceles triangle, like I never drew up an isosceles triangle, gave sides proper length for the angles, and saw if you could get c^2 to equal a^2+b^2 in even one case, because I dismissed the statement immediately because it said any two sides
okay I did not do that
I proved it is not possible for 2sqrt(a) = sqrt(b)
since you said roots originally
proof is the same regardless actually
the 4 is just replaced with a sqrt(2)
wait
but then the 2a is sqrt(2)/2
I actually have to check this case 1 second
the one I posted has 3 sides
the hypotenuse is length a
we don't know the other side, but one side is 2a
because for our original isosceles triangle, I chose the two equal sides to be equal to a
