general

4e^(2x)=5

for the life of me i cant figure it out even though i KNOW it should be easy

ln

wait

i just realized im a dumbass

2x = ln(5/4)

for literally 20 minutes

i forgot that i can fucking divide both sides by 4

instead of taking ln4e

you can still do it if you play with the adding rule

yeah but i was confusing the fuck out of myself

wait

if i have logx+log(x-3)=1

and then have log(x^2-3x)=1

what do i do from there?

do i assume the base is 10 and then go from there?

i guess

is there any other way to do it?

i don't know

it seems pretty effective

so im fucked in summer work right now, right?

i turn on spotify, first song that plays?

drowning

x^2 - 3x = 10

yeah i know it from there

i just didnt know if thats an acceptable way of doing it, fuck it tho

(x-5)(x+2) = 0

x = {5,-2}

not -2. somce ;pgs

since logs*

how do i do:

(x-5)/(x-3) ≥ 0

its a range

or multiple ranges

well yeah

but how do i solve it?

no thats right

which one?

x > 5 U x < 3

how do i arrive at that answer though

x is greater than or equal to 5

not just greater than

ah

how do i arrive at that answer

i just plotted it in my head

you need to look where x<0 or equal to zero

so 5

is where its 0

If you need to show your work, make a table

or make a 1 axis plot

alright

at the different points

just analyze the zeros of the top and bottom and check around them

different key points

yeah what leg said

what is the behavior > and < 3 and 5

so x<3 and x≥5

yes

since anything else is either negative or not defined

what is the formula for inverse sine?

is it inverse sine + 2pin and then inverse sine (90-x) +2pin

hell if I know

what?

you are not far enough to need to know this

yeah

im taking ab not bc btw

i dont have the time for bc

this isn't bc, this is like post calc 3

complex exponentials don't come up until differential equations

yeah, I have barely delt with complex and I am in university potahto, no clue what you are talking about

oh i wasnt talking about doing that

im just saying im not taking bc

i would probably drop on the spot of i had to do that this year

Prob would be wise if the expected you do do post calc 3 stuff lol

lol

okay so (x+1)^2(x-2)+(x-2)^2)(x+1)=0

Pfff, I have no idea how to do that Kappa

plz

its the last question on this page