general

not 7/5

engineering?

7/2 yeah my b

ece

ece?

electrical and computer engineering

okay

when you add 2 logs do you multiply the insides?

if they have the same base?

or do you just add the inside?

multiply

i thought it was the inverse of what you just said

and divide when subtracting?

And divide if subtract

por ejemplo

2log(x-3)+log(x+2)-6log(x)

-4log((x-3)(x+2)/(x))?

bring the multiplies into the log

wut

2log(x-3)= long (x-3)^2

long

long!

long lol

log*

but like

x^6?

oh boi

yes

a*log(b) = log(b^a)

yes i know that

as a log rule

but that seems hard XD

its not

what are you even solving for?

no clue how much it wants you to simplify

im simplifying

there is nothing to reduce in these questions though

I would assume log (

i mean thats what i have

its just changing the form

i dont feel like it would be necessary to go further

cause it wont simplify any more

I assume he is just being made to practice log rules leg

then he should be told to condense the logs

Probably, but I imagine this is what is needed

the coolest log formula is log_a(x) = log_b(x)/log_b(a)

is that what I wrote here

converthing bases

yes

yeah

that is a cool formula

its actually quite useful for computer science runtime analysis

I can imagine

I like how I now have two different people to ask me questions Kappa

Been helping Umbreon with his physics and math

why do probability professors make such a big deal over Bayes theorem?

No idea, considering I do not know what that is

its such an easy to grasp concept

its just an equation for determining probability of future events based on prior knowledge

Have not done anything probability in uni yet

third year hype

alright

got another

ima just take a pic of this one

How to do m

what is the second exponent?

and exponent to an exponent do you add or mulitply?

second is -1/2

pic is pretty clear

i think

i have no idea what to do here

let r = (1-2x)^(-1/2) r(1+xr^2)

ok

go on

r(1+x/(1-2x))

then multiply top and bottem by sqrt 1-2x?

then do more stuff?

that just returns it back to the original problem

so leave it like that?