general

well I mean I learned that

are you still dieing to homework @legorhin

not really

my group project that i pretty much soloed was done today

you cant have a limit that is an imaginary number right?

rip leg

why not?

because I dont know

I dont know how to calculus

you can

rip

I have no idea how to answer this then

but your math classes will pretend you can't unless you go into mathematics or electrical/computer engineering

"explain why you can not use substitution to find the limit" lim of rad(x-2) as x approaches -2

the implicit scope of your class is to deal with only real numbers

"forget" about i until later

but

we learned that in algebra

I dont afraid of no is

you are nowhere near the level of math that will actually be finding limits in the complex domain

oh

or doing complex calculus

we just call that "undefined"

so we dont give no shits about no is

checked the answer key

what is rad(x)?

(x)^(1/2)

sqrt...

oh

yeah

that isnt really descriptive

rad could be a couple things

idk where I thought of that

yeah it really could be

what is it called when you get 0/0 through substitution?

L'Hospital's rule?

ok google L'Hospital's rule

http://tutorial.math.lamar.edu/Classes/CalcI/LHospitalsRule.aspx

indeterminate form

so (sin(x))/(-2(3.14...)</=x<0) does not work in my calculator

how would I go about doing this @legorhin

what?

essentially what I am trying to do is limit the function to (-2(3.14...)</=x<0)

what is </=

(sin(x))/(x<0) works

that is less than or equal to

<= is the programmers way of showing that

ok

is it >= or =>

out of curiosity

>=

double character operators with = in them almost always end with it

anyway

how would I do that

sin(x)/2π <= x < 0

sin(x) <= 2πx < 0

well

the first one does not show up at all

rip

sin(x)/x <= 2π < 0

disproven

sinc(x) <= 2π < 0

though 2π == 0 in some cases

well I guess I need a new mouse mat

my cursor keeps drifting and apparently it is my old one

it works better on hardwood with random gaps in it than on a mat lol

but leg I have no idea what you are trying to get me to do

its signal processing stuff

i don't know what you are trying to do either

well

I am an idiot

who does not explain things when asking for help

god fucking damn it

since x has to be less than 0, you can divide the sin by x without worrying about illegal division

graph this (sin(x))/(-2(3.14...)<=x<0)

also

the division thing

I dont know what that works

-2π?

I just learned it tioday lol