the-dump

@taxes: 6d20kl1 = (17+20+10+7+8+1) = 1

bad example

/r 6d20

@Rusp: 6d20 = (17+12+4+12+16+14) = 75

/r 6d20kl1

@taxes: 6d20kl1 = (1+18+6+11+20+12) = 1

why

/r 6d20kl1

@taxes: 6d20kl1 = (12+8+13+7+10+20) = 7

THER

ok but

what’s the point of this

/r repeat (d6, 3, brief)

@taxes: repeat (d6, 3, brief) = 5, 2, 5

/r 6d20kl15

@Deleted User: 6d20kl15 = (18+11+19+4+1+11) = 64

/r 1d20r1

@taxes: 1d20r1 = (6) = 6

huh

/r 1d20r1

@taxes: 1d20r1 = (13) = 13

/r 2d20r1

@taxes: 2d20r1 = (19+5) = 24

/r1

i dont understand

"/r 1d20r1 - Roll twenty, reroll on one (because halflings are lucky)."

OH

reroll on a 1

i wana see this work

/r 2d20r1

@taxes: 2d20r1 = (3+17) = 20

/r 2d20r1

@taxes: 2d20r1 = (13+20) = 33

/r 2d20r1

@taxes: 2d20r1 = (12+8) = 20

/r 20d20r1

@Deleted User: 20d20r1 = (11+17+14+18+9+2+17+17+6+20+7+7+2+18+15+1+5+17+8+17+13) = 240

/r d20+11

@Rusp: d20+11 = (14)+11 = 25

/r d20+11

@Rusp: d20+11 = (4)+11 = 15

/r 3d6!

@taxes: 3d6! = (6+1+5+4) = 16

i dont know what exploding dice is

/r 3d6!

@taxes: 3d6! = (3+3+2) = 8

/r 3d6!

@taxes: 3d6! = (2+4+3) = 9

OH

if you get the highest number

it keeps going

/r 3d2!

@taxes: 3d2! = (2+1+2+2+1+1) = 9

/r d6!

@taxes: d6! = (5) = 5

wait

idea

/r d1!

@taxes: d1! = (1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1) = 32

rip it stops

/r d2!

@taxes: d2! = (1) = 1

ok

/r d2!

@taxes: d2! = (2+2+2+2+2+1) = 11

yes

an 11 chain, nice

/r d2!

@taxes: d2! = (1) = 1

oof

/r d2!

@taxes: d2! = (1) = 1

/r d20!

@Deleted User: d20! = (16) = 16

/r 10d8

@Rusp: 10d8 = (4+3+1+8+5+3+8+2+1+5) = 40

exactly average

wonderful

/r d20!