children-at-play
<:PokemonThink:593970343786577967> <:dab:525968335347646495> Practice running a third world country amidst a global pandemic.
Thursday, January 12, 2017
who the math peoples again?
@Phijkchu_Pikachu are you a chem major or math major? i forgot
Mathmatical physics
so you know precalc is what you are saying
depends
the fuck is precalc
is it limits
identities
I am Canadian, I do not know your ways
sines and cosines and tans
boring
I know some of that
those are second nature to signal processing focusses
so i have this identity that i have to prove
post it
deja vu
is this nintendo switch related Kappa
clearly
left side is (cos(1/2x)+sin(1/2x)) /( cos(1/2x)-sin(1/2x))
i want to eat food but to hot rip hype?
trying to get to sec + tan
i think
question is
i wanna multiply the bottem by the conjugate
secx tanx?
but not sure exactly what that would do
would it give me cos^2(1/2x) - sin^2(1/2x)
is it x/2 or 1/(2x)?
as in like half angle identities 1/2
also is it secx tanx or sec(1/2x) tan(1/2x)
you did not specify
but i dont wanna expand to half angle identities cause that is hell
secx tanx not sec(1/2x)
http://www2.clarku.edu/~djoyce/trig/halfangleformulas.jpg
i know that
shut up leghorin
if i did that
it would create literal hel
It has been a while since I have done trig proofs
what im saying
give me a min
wait just tell me if this is right
multiply bottem by conjugate
I am thinking about that
gets me cos^2(x/2) - sin^2(x/2)
which i can bring out the double angle identity
cos2(x/2)
or just cosx
does that work?
is this x/2 or 1/2z
(1/2)(x)
I was about to say
OH WAIT
I THINK IT WORKS
I ended up with 1-2sin^2(x/2) on the bottom
seems likely
cause top would be cos^2(x/2) + sin^2(x/2) + 2sin(x/2)cos(x/2)
which would be 1+2sin(x/2)cos(x/2)
there you go
which is 1 + sin2(x/2)
so 1 + sin / cos
or secx + tanx
alright
Follow up question for leg
have you ever used an oscilloscope
and is it difficult to use