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Phi Kappa Chi ΦΚΧ <a:yeah:589703000977571860><a:ppHop:536353159615086612>

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Phijkchu_Pikachu banned-users
for every epsilon greater than 0 there exists a delta greater than 0 such that |x-a| is less than delta implies such that |f(x)-L| is less than epislon implies the limit as x goes to a of f(x) is L

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