banned-users

he initially wrote (x+1)^2(x-2)+(x-2)^2)(x+1)=0

I have 4 pages of different math and physics problems between this lad and umbreon NotLikeThis

which is much easier

no complex roots

but the wolfram page changed the second x-2 to x+2

lmao

if he typoed the wolfgram, then that makes my origional guess right

(x + 1) (x - 2) (2 x - 1)

aka what I said it should include

(x+1)(x-2)(x+1+x-2)

(x+1)(x-2)(2x-1)

logs of negative numbers are definitely a thing because of how complex exponents work

it reduces to ln(|x|) + iπ

Dear lord

It begins

Taking all bets

how long until someone such as sargon gets hit

well youtube is going to die soon

alright

i found a problem that i high key have never even seen before

top one

bad picture

cannot see

but pikachu

k

one sec

somebody might get offended by that video

even though

it has cold

hard

facts

you see pikachu

the truth is offensive

and that is wrong

Using the table of values given above, find the average change for f on the interval (2,5) and write an equation for a secant line passing through the corresponding points

lieing is the only way

average the difference of each change

2, 7, 1, 5, 2, -5

12/2 = 6

im sorry if I am cutting you off potahto, I am just pissed off and ranting after a forced diversity assembly

x: 0 1 2 3 4 5 6 f(x): -10 -8 -1 0 5 7 2

Do not know about the -5

I think it is absolutle change leg

did you learn about all the minority students that were allowed in because of their diversity instead of their merit?

I think it should be 17/2

average rate of change is 2?

no

average change not rate

oh

and leg posted the changes, 2, 7, 1, 5, 2, 5

so 1, 5, 7

that is how much each value changes

between the next

but its only between 2,5

so just 1 5 and 7?

yeah I guess

so 13/3

then the secant is just the line that goes through those two points

straight line

what 2 points tho?

rather

f(2)

f(5)

okay

so a secant line going through 2,-1 and 5,7?

yes

that is all that question wants

so 2sec(x+45ish) or something?

i can figure that out i think

no

what

secant lines dont actually have secant

secant is a straight line through two points on a function

its just a y=mx+b

^

OH