banned-users

and i didn't read it right Keeper

ignore me

wait

where do you see that?

tbf what he wrote originally is completely diferent from the linked problem

oh ffs

you can hit more forms

I wager it will be a (2x +a)(x+b)(x+c)

that would have been so useful

with the a,b,c including a 1 2 and a 3

wait

not 3

fuck

fml i multiplied wrong

two 1s and a 2

since there is a 5, the 2 needs to multiply with the wx

2x

so it is not the a

so I think prob 2x+1

one route is -1

x+2

x+1

or that

it only lists one real root as -1 lol

wait

i see the path

i think

so synthetic divide by -1

yeah

yeah

i did

breaks down into x+1

and 2x^2+3x+2

2x^2 +3x +1?

+2*

yeah

that only has imaginary roots

i got them

checked by completing the square

?

solveing atm

is the question this: (x+1)^2(x-2)+(x+1)(x+2)^2 or this: (x+1)^2(x-2)+(x+1)(x-2)^2

I am getting

-9 +/- i sqrt(27) all over 16

as your roots

wat

23

not 27

squrt 27 = 3sqrt(3)

did i fuck up the quadratic formula?

Should be completing the square for this

why?

Idk, makes more sense to me

are you sure you put the correct formula in wolfram? the thing you wrote initially didn't have complex roots

gimme 15, grabbing lunch

wait no

im finishing this now

so i have 2x^2+3x+2

so -3+sqrt(9-16)/4?

right?

+/-

sqrt -5 KappaG

if that is equivelant to the following, yes

unless I did my math wrong

im confuse

nope

not equivalent

wtf am i doing wrong?

trying to use the quadratic formula to find complex roots

completing the square is easier

explain?

wait

I am retarded

trie

forgot to divide the 2 by 2

1 sec

im just confused at this point, like how am i fucking up the quadratic formula