banned-users

how do i arrive at that answer

i just plotted it in my head

you need to look where x<0 or equal to zero

so 5

is where its 0

If you need to show your work, make a table

or make a 1 axis plot

alright

at the different points

just analyze the zeros of the top and bottom and check around them

different key points

yeah what leg said

what is the behavior > and < 3 and 5

so x<3 and x≥5

yes

since anything else is either negative or not defined

what is the formula for inverse sine?

is it inverse sine + 2pin and then inverse sine (90-x) +2pin

hell if I know

what?

you are not far enough to need to know this

yeah

im taking ab not bc btw

i dont have the time for bc

this isn't bc, this is like post calc 3

complex exponentials don't come up until differential equations

yeah, I have barely delt with complex and I am in university potahto, no clue what you are talking about

oh i wasnt talking about doing that

im just saying im not taking bc

i would probably drop on the spot of i had to do that this year

Prob would be wise if the expected you do do post calc 3 stuff lol

lol

okay so (x+1)^2(x-2)+(x-2)^2)(x+1)=0

Pfff, I have no idea how to do that Kappa

plz

its the last question on this page

i expanded it to 2x^3-3x^2-3x+2

wait

I am confused as to what the question is

those parentheses don't match up

okay

that makes much more sense

I thought the x-2 was in the exponent

im shit at long dividing

(x+1)(x-2)(x-1)

your three roots

1 step

Yeah, it is clear there must be a 2, 1, and a 1 in this

and i didn't read it right Keeper

ignore me

wait

where do you see that?

tbf what he wrote originally is completely diferent from the linked problem

oh ffs

you can hit more forms

I wager it will be a (2x +a)(x+b)(x+c)

that would have been so useful

with the a,b,c including a 1 2 and a 3

wait

not 3

fuck

fml i multiplied wrong

two 1s and a 2

since there is a 5, the 2 needs to multiply with the wx

2x

so it is not the a

so I think prob 2x+1

one route is -1

x+2

x+1

or that

it only lists one real root as -1 lol

wait

i see the path

i think

so synthetic divide by -1