@legorhin:
$e = e^ln((10)) = 10.000000000000002
Phi Kappa Chi ΦΚΧ <a:yeah:589703000977571860><a:ppHop:536353159615086612>
$e = e^ln((10)) = 10.0000000000000021 = 1 = 11d20k0 = (1d20 = (16) = 161d20!>1k1 = (2d2k1 -1 = (1d20 = (19) = 191d20!>1kl1 = (1d20 = (14) = 14