@legorhin: 1+17) = 17
$d20 = (
Phi Kappa Chi ΦΚΧ <a:yeah:589703000977571860><a:ppHop:536353159615086612>
$d20 = (e^ln(1d20) = e^ln((2)) = 1.9999999999999998Roll saved. The server is using 0 out of 128 rolls.
$e = e^ln((1)) = 13d20 = (18+20+6) = 44Roll saved. The server is using 1 out of 128 rolls.
$trihex = (12+4+13) = 29