It's useful for if you're rolling kobolds I guess
banned-users
Phi Kappa Chi ΦΚΧ <a:yeah:589703000977571860><a:ppHop:536353159615086612>
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Wednesday, June 14, 2017
/r 4dF
@legorhin:
4dF = (+b++) = 3/r 2d20k1
@VinnyG: 5+17) = 17
2d20k1 = (/r repeat (4d6k3,6)
@legorhin: 2+2) = 10, (6+4+5+6) = 17, (3+5+6+3) = 14, (1+4+5+5) = 14, (1+1+4+6) = 11, (1+2+1+1) = 4
repeat (4d6k3,6) = (3+5+I'm sure you can make it take a 1 or 20 over anything else I just don't know how
/r 5d20=20
@legorhin: 12 14 3 15 15, 0 successes) = 0
5d20=20 = (like that?
Sure
/r 3d6!
@legorhin:
3d6! = (1+2+4) = 7/r 210d20!
@legorhin:
210d20! = (9+8+20+16+14+3+14+11+19+17+13+18+19+10+12+9+16+13+16+12+6+14+6+2+3+5+6+7+17+20+15+2+12+10+4+16+12+14+20+2+20+13+2+11+10+19+1+17+17+4+17+12+12+8+9+12+1+12+5+17+2+20+3+15+1+6+12+6+6+9+19+12+3+19+14+8+2+2+7+17+1+7+12+16+1+20+4+9+9+14+17+1+7+12+4+11+4+10+12+14+3+8+13+8+5+19+13+1+19+14+4+16+20+16+7+7+15+9+18+4+6+15+2+7+2+16+3+7+2+6+14+7+1+10+5+1+9+17+16+14+1+15+18+13+12+8+19+19+13+15+5+16+3+11+19+4+15+5+19+19+2+11+19+17+20+3+20+12+7+3+4+14+17+20+2+6+17+17+15+9+13+6+3+2+4+17+7+11+1+20+1+16+4+5+20+4+14+8+8+20+16+7+17+5+8+18+4+19+9+9+18+3+15+17+20+10+20+19+12+12+14+9+16+16+14) = 2423You got so many 20s
/r 20d20!>10
@legorhin:
20d20!>10 = (12+13+1+10+1+3+19+17+5+19+15+3+12+11+8+6+13+7+20+18+7+11+7+12+17+12+4+11+4+2+15+4+16+10+10+16+1+6+8+13+4+9+11+6) = 429/r (600d20)/600
@Phijkchu_Pikachu: Grog!
/r 210d20=20
@VinnyG: Muffliato!
/r 10d20=19
@Phijkchu_Pikachu: 6 17 4 12 17 11 11 7 1 19, 1 success) = 1
10d20=19 = (/r 20dF
@legorhin:
20dF = (+++-bb+b+-b-bb-b-++b) = 2/r 2d20k1k20
@VinnyG: 13+20) = 20
2d20k1k20 = (roll 20 dice, check if all 20 are 20s, if they all are, you get your crit
hard mode
/r 1d20!1k1
@legorhin:
1d20!1k1 = (6) = 6/r 20d20!1k1
@legorhin: 18+5+18+5+10+1+2+19+18+20+17+2+6+8+16+6+5+14+11+7+20) = 20
20d20!1k1 = (/r repeat (2d20k1k20,7)
@VinnyG: 2+13) = 13, (5+6) = 6, (2+20) = 20, (12+7) = 12, (17+2) = 17, (17+17) = 17, (19+17) = 19
repeat (2d20k1k20,7) = (Hmm
/r 20d20!1k20
@legorhin:
20d20!1k20 = (15+2+18+6+18+11+16+15+19+15+14+19+17+20+6+4+5+17+16+12) = 265/r 20d20!1k20
@legorhin:
20d20!1k20 = (10+3+6+5+12+19+3+4+18+3+17+8+12+15+13+6+11+18+3+16) = 202/r 2d20k1
@VinnyG: 12+17) = 17
2d20k1 = (/r 2d20=1=20
@VinnyG: 19 18, 0 successes) = 0
2d20=1=20 = (/r 5d20kl1
@legorhin: 19+18+9+19+9) = 9
5d20kl1 = (/r repeat (2d20=1=20,6)
@VinnyG: 4 1, 0 successes) = 0, (8 13, 0 successes) = 0, (3 4, 0 successes) = 0, (13 19, 0 successes) = 0, (3 16, 0 successes) = 0, (5 7, 0 successes) = 0
repeat (2d20=1=20,6) = (/r $test 5d20
@legorhin: Finite Incantatem!
I think my statement is flawed there.
/r $persuasion = 5d20
@legorhin: $persuasion
5d20 = (14+3+17+1+1) = 36Roll saved. The server is using 0 out of 128 rolls.
/r $persuasion
@legorhin:
$persuasion = (18+13+13+17+13) = 74sweet
/r $persuasion =
@legorhin: $persuasion was removed!
lmao what
/r $d20 = 1d20!1k1
@legorhin: $d20 1+11) = 11
1d20!1k1 = (Roll saved. The server is using 0 out of 128 rolls.
/r $d20
@legorhin: 1+17) = 17
$d20 = (Explain?
you can save roll macros
/r $d20 =
@legorhin: $d20 was removed!
he's making variables
But why
because he has nothing better to do
so you don't have to type ou tthe entire thing every time
interesting
/r $e = e^ln(1d20)
@legorhin: $e
e^ln(1d20) = e^ln((2)) = 1.9999999999999998Roll saved. The server is using 0 out of 128 rolls.
/r $e
@legorhin:
$e = e^ln((1)) = 1/r $e
