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Noice Noice

nazi Twitch

Let f be the function defined by f(x) = x^3 + x. If g(x) = f'(x) and g(2) = 1, what is the value of g'(2)?

g(2) can't equal 1

leg

why do you need g(2) = 1

g(2) can equal 1

MATH FIGHT

NERDS

c = -12

its not an integral NotLikeThis

It can be

no shit

its derivatives

square both sides

^

3x^2+1

x=2

13, not 1

why am I adding a plus c

why can g(2) = 1

Just taylor expand about x=5

I don't even

10_19 is the only Choice Kappa

This question is fundementally broken

true

scratch it out and write a new question

like 11 is the perfect age Keepo

no answer?

that is not what you typed

this has a solution

Let f be the function defined by f(x) = x^3 + x. If g(x) = f'(x) and g(2) = 1, what is the value of g'(2)?

no

fuck

fucking

inverses

gdi

x= y^3 + y

take derivative with respect to x, use chain rule, factor out the extra dy/dx

have fun doing that when you don't need to

Kek

i'm getting sqrt(1/3)

that can't be right

1/4

We got it leg

1/4 leg

you do need the g(2) = 1

27

how tho

nvm

if its 24 the second derivative will be 0

lower the first derivative won't work

I think I got it

yeah

@xBrox Back

its 0 pika