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oh do you ru much?

theres a diference

doin a science project with one

damn

anyone have experience with an arch height index measurement system?

oh, have any of you worked with human performance and feet?

alright

or secx + tanx

so 1 + sin / cos

which is 1 + sin2(x/2)

which would be 1+2sin(x/2)cos(x/2)

cause top would be cos^2(x/2) + sin^2(x/2) + 2sin(x/2)cos(x/2)

I THINK IT WORKS

OH WAIT

(1/2)(x)

does that work?

or just cosx

cos2(x/2)

which i can bring out the double angle identity

gets me cos^2(x/2) - sin^2(x/2)

multiply bottem by conjugate

wait just tell me if this is right

is

what im saying

l

it would create literal hel

if i did that

shut up leghorin

i know that

so

secx tanx not sec(1/2x)

but i dont wanna expand to half angle identities cause that is hell

as in like half angle identities 1/2

x/2

would it give me cos^2(1/2x) - sin^2(1/2x)

but not sure exactly what that would do

i wanna multiply the bottem by the conjugate

question is

i think

trying to get to sec + tan

left side is (cos(1/2x)+sin(1/2x)) /( cos(1/2x)-sin(1/2x))

so i have this identity that i have to prove

okay

sines and cosines and tans

identities

so you know precalc is what you are saying

@Phijkchu_Pikachu are you a chem major or math major? i forgot

who the math peoples again?

hey

im sick af on new years, hatin lyfe