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what is the formula for inverse sine?

so x<3 and x≥5

alright

is where its 0

so 5

how do i arrive at that answer

how do i arrive at that answer though

which one?

but how do i solve it?

well yeah

(x-5)/(x-3) ≥ 0

how do i do:

since logs*

not -2. somce ;pgs

i just didnt know if thats an acceptable way of doing it, fuck it tho

yeah i know it from there

drowning

i turn on spotify, first song that plays?

so im fucked in summer work right now, right?

is there any other way to do it?

do i assume the base is 10 and then go from there?

what do i do from there?

and then have log(x^2-3x)=1

if i have logx+log(x-3)=1

wait

yeah but i was confusing the fuck out of myself

instead of taking ln4e

i forgot that i can fucking divide both sides by 4

for literally 20 minutes

i just realized im a dumbass

wait

for the life of me i cant figure it out even though i KNOW it should be easy

4e^(2x)=5

alright

warning: i may soon need more help on math/apchem

i have to go for a run could you pm me the solution if you can figure it out?

yeah

-3/2 and -1/2

we is confuse

it literally just said "simplify" and then listed a shit ton of expressions

so leave it like that?

then do more stuff?

then multiply top and bottem by sqrt 1-2x?

go on

ok

i have no idea what to do here

i think

pic is pretty clear

second is -1/2

and exponent to an exponent do you add or mulitply?