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Phi Kappa Chi ΦΚΧ <a:yeah:589703000977571860><a:ppHop:536353159615086612>
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Saturday, May 7, 2016
hold on
I think I could do something here...
y(x) = c1 e^(-x/2) sin((sqrt(3) x)/2)+c2 e^(-x/2) cos((sqrt(3) x)/2)+x-1
i used the internet because I can't be bothered to look up how to solve these
this is as far as I got: y = d (-dy -y +xt^2)
thats not valid in any way
I probably broke some rule somewhere
and there was no t in the original
nvm
whoops
d²y/dt² + dy/dt + y = x
y''+y'+y=x
thats better
solve for y?
its the same thing
y = x - y'' - y'
Kappa
again I'm wrong
adding t makes that too complicated
not what i meant
y''+4y'+4y = xis alot easierwhy is there a random floating apostrophe?
or is that like a double prime or something?
yeah
y = (x - y'' - 4y')/4
Kappa
how does this even work
i forget
first you put all the y differentials on one side and solve that for zero
what about the x?
more work
it involves itegrals and some stuff you need to memorize
integral proteins?....
Keepo
Kappa
the quadratic formula is actually used to solve for zero
(-b +/- rad(b^2 -4ac))/2a
that?
yup
neat
only you use the order of differentiation instead of the exponent
so
y''+2y'+2y=0reduces to1,1then because magic you get
y(t)=c1e^(t)+c2te^(t)KALEC WAS RIGHT
